Search the Community
Showing results for tags 'column shear'.
-
Asalamualaikum, If I know any column section, I can compute its section capacity in terms of yield moment using SAP section analysis or Response 2000 softwares. But if I want to find whether a column is failing in shear or not, what procedure should I use? For example, I have a column of 6'' x 18'' with 6 #4 bars and ties of #3@6'' c/c. I have done pushover analysis on software, Now I want to check whether column is safe in shear or not. So I note down the internal shear forces of column from the software at each step of pushover analysis and manually compare them with column shear capacity using ; Column shear capacity = Shear force resistance due to concrete (2 * lamda* fc'^1/2 * bd) Is this the correct method? or do I need to consider ties as well in resisting shear? If yes, then Vs=Avfyd/s formula will be used for ties resistance or something else? Thanks for the help
-
MIDAS SET Column Concrete Shear Capacity Problem MIDAS SET 3.2.1 Column Concrete Shear Capacity Problem Link for CIVILEA topic MIDAS SET is a good tool to verify individual sections output. It incorporates a simple input data form on the left side and the detailed equations and output in the right pane. Despite of its good tools and features, I faced a problem while I was calculating the column shear capacity (concrete) manually and trying to verify it with MIDAS. To my astonishment it gave me almost double the value which I got using ACI-318 chapter 11 equation 11-4 for concrete shear capacity under axial loads. I will show you here the detailed steps to prove my point. If you find anything misleading or want to share your thoughts please respond. I have written an email to MIDAS and let’s see when can I get the response. Solve a simple column example B=500mm H=500mm Cover=50mm so d = 450mm Axial Factored Load is 700kN Compression f’c = 45 MPa Ag = 500x500 = 500 mm² From ACI-318(05M) chapter 11, equation 11-4 we get; Vc = 0.17 (1 + Nu/14Ag) (f’c^0.5) b.d Where Nu/Ag term should be in N/mm² Nu is –ve for TENSION and +ve for compression So putting all these values in this equation we get; Vc = [ 0.17 ( 1 + 700*1000/14/500² ) (45^0.5) 500 x 450 ] / 1000 = 307.91 kN and Phi Vc = 0.75x307.91 = 230.93 kN whereas in MIDAS software, it gives Phi Vc in both the directions equal to 612.0 kN. This value is even more than 2 times the value we calculated from ACI equation. I am doubtful to use this software for verification because of this error.